27x+3(x-5)=50

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Solution for 27x+3(x-5)=50 equation:



27x+3(x-5)=50
We move all terms to the left:
27x+3(x-5)-(50)=0
We multiply parentheses
27x+3x-15-50=0
We add all the numbers together, and all the variables
30x-65=0
We move all terms containing x to the left, all other terms to the right
30x=65
x=65/30
x=2+1/6

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