27x-12-14x+7=2(4x-6)+23

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Solution for 27x-12-14x+7=2(4x-6)+23 equation: 



27x-12-14x+7=2(4x-6)+23

We move all terms to the left:

27x-12-14x+7-(2(4x-6)+23)=0

We add all the numbers together, and all the variables

13x-(2(4x-6)+23)-5=0



We calculate terms in parentheses: -(2(4x-6)+23), so:

2(4x-6)+23

We multiply parentheses

8x-12+23

We add all the numbers together, and all the variables

8x+11

Back to the equation:

-(8x+11)



We get rid of parentheses

13x-8x-11-5=0

We add all the numbers together, and all the variables

5x-16=0

We move all terms containing x to the left, all other terms to the right

5x=16

x=16/5

x=3+1/5

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