27x-5=(4x-2)/5

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Solution for 27x-5=(4x-2)/5 equation:



27x-5=(4x-2)/5
We move all terms to the left:
27x-5-((4x-2)/5)=0
We multiply all the terms by the denominator
27x*5)-((4x-2)-5*5)=0
We add all the numbers together, and all the variables
27x*5)-((4x-2)=0
Wy multiply elements
135x^2=0
a = 135; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·135·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{270}=0$

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