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27x^2+1=180
We move all terms to the left:
27x^2+1-(180)=0
We add all the numbers together, and all the variables
27x^2-179=0
a = 27; b = 0; c = -179;
Δ = b2-4ac
Δ = 02-4·27·(-179)
Δ = 19332
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{19332}=\sqrt{36*537}=\sqrt{36}*\sqrt{537}=6\sqrt{537}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{537}}{2*27}=\frac{0-6\sqrt{537}}{54} =-\frac{6\sqrt{537}}{54} =-\frac{\sqrt{537}}{9} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{537}}{2*27}=\frac{0+6\sqrt{537}}{54} =\frac{6\sqrt{537}}{54} =\frac{\sqrt{537}}{9} $
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