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27x^2+27x+6=0
a = 27; b = 27; c = +6;
Δ = b2-4ac
Δ = 272-4·27·6
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-9}{2*27}=\frac{-36}{54} =-2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+9}{2*27}=\frac{-18}{54} =-1/3 $
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