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27x^2+3=18x
We move all terms to the left:
27x^2+3-(18x)=0
a = 27; b = -18; c = +3;
Δ = b2-4ac
Δ = -182-4·27·3
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{18}{54}=1/3$
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