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27x^2-23x-54=0
a = 27; b = -23; c = -54;
Δ = b2-4ac
Δ = -232-4·27·(-54)
Δ = 6361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-\sqrt{6361}}{2*27}=\frac{23-\sqrt{6361}}{54} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+\sqrt{6361}}{2*27}=\frac{23+\sqrt{6361}}{54} $
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