27x2-24x+5=0

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Solution for 27x2-24x+5=0 equation: 



27x^2-24x+5=0

a = 27; b = -24; c = +5;
Δ = b2-4ac
Δ = -242-4·27·5
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-6}{2*27}=\frac{18}{54}
=1/3
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+6}{2*27}=\frac{30}{54}
=5/9
$

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