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27x^2=27
We move all terms to the left:
27x^2-(27)=0
a = 27; b = 0; c = -27;
Δ = b2-4ac
Δ = 02-4·27·(-27)
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2916}=54$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-54}{2*27}=\frac{-54}{54} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+54}{2*27}=\frac{54}{54} =1 $
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