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27x^2=92x
We move all terms to the left:
27x^2-(92x)=0
a = 27; b = -92; c = 0;
Δ = b2-4ac
Δ = -922-4·27·0
Δ = 8464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8464}=92$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-92)-92}{2*27}=\frac{0}{54} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-92)+92}{2*27}=\frac{184}{54} =3+11/27 $
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