If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x in (-oo:+oo)
27*x = (1/9)*x-5 // - (1/9)*x-5
27*x-((1/9)*x)+5 = 0
27*x+(-1/9)*x+5 = 0
242/9*x+5 = 0 // - 5
242/9*x = -5 // : 242/9
x = -5/242/9
x = -45/242
x = -45/242
| 1.4(2-x)-0.5(2x-4)=0findx | | (5/9)/t=1/5 | | 1.4(2-x)-0.5(2x-4)=0 | | 16y+8=16y+8 | | 2t-4t=7 | | 20+2y=-20 | | 120=(-30)-5x | | 16x=1/4x-5 | | 5/x-1=10/x-9 | | 5x+6x+(160-4x)=300 | | 7[x+9]=7x+63 | | 4/d=45/15 | | x=100+1x | | 3x^2-9xy-30y^2=0 | | 5/6x-5=-4 | | x=100+2.0x | | 7[x+9]=16x-63 | | 7[x+1]=7x-9 | | -12+2y=-12 | | 185+90+25=180 | | 7(x-7)=7x-14 | | 9a^3+66a^2-48a=0 | | 4/3t=9/8 | | 12y+6=10y+10 | | (b+3)(b+2)=0 | | 11x^2+12x+9=0 | | 8(X-4)=12x+32 | | -1(11x^2+12x+9)=0 | | 3ax^2+16ax+21a=0 | | (2x+8)(x+10)=0 | | (p-7)(p+8)=0 | | 3(2x^2+x-10)=0 |