27y-18=3(9y-6)

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Solution for 27y-18=3(9y-6) equation: 



27y-18=3(9y-6)

We move all terms to the left:

27y-18-(3(9y-6))=0



We calculate terms in parentheses: -(3(9y-6)), so:

3(9y-6)

We multiply parentheses

27y-18

Back to the equation:

-(27y-18)



We get rid of parentheses

27y-27y+18-18=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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