27y-3=3(9y-1)

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Solution for 27y-3=3(9y-1) equation: 



27y-3=3(9y-1)

We move all terms to the left:

27y-3-(3(9y-1))=0



We calculate terms in parentheses: -(3(9y-1)), so:

3(9y-1)

We multiply parentheses

27y-3

Back to the equation:

-(27y-3)



We get rid of parentheses

27y-27y+3-3=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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