28(2)+b(2)=50(2)

Solution for 28(2)+b(2)=50(2) equation:

28(2)+b(2)=50(2)

We move all terms to the left:

28(2)+b(2)-(50(2))=0

determiningTheFunctionDomain
b2+282-502=0

We add all the numbers together, and all the variables

b^2-220=0

a = 1; b = 0; c = -220;
Δ = b2-4ac
Δ = 02-4·1·(-220)
Δ = 880
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{880}=\sqrt{16*55}=\sqrt{16}*\sqrt{55}=4\sqrt{55}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{55}}{2*1}=\frac{0-4\sqrt{55}}{2}
=-\frac{4\sqrt{55}}{2}
=-2\sqrt{55}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{55}}{2*1}=\frac{0+4\sqrt{55}}{2}
=\frac{4\sqrt{55}}{2}
=2\sqrt{55}
$