28(2c+3)=2(c+5)+c

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Solution for 28(2c+3)=2(c+5)+c equation:


Simplifying
28(2c + 3) = 2(c + 5) + c

Reorder the terms:
28(3 + 2c) = 2(c + 5) + c
(3 * 28 + 2c * 28) = 2(c + 5) + c
(84 + 56c) = 2(c + 5) + c

Reorder the terms:
84 + 56c = 2(5 + c) + c
84 + 56c = (5 * 2 + c * 2) + c
84 + 56c = (10 + 2c) + c

Combine like terms: 2c + c = 3c
84 + 56c = 10 + 3c

Solving
84 + 56c = 10 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
84 + 56c + -3c = 10 + 3c + -3c

Combine like terms: 56c + -3c = 53c
84 + 53c = 10 + 3c + -3c

Combine like terms: 3c + -3c = 0
84 + 53c = 10 + 0
84 + 53c = 10

Add '-84' to each side of the equation.
84 + -84 + 53c = 10 + -84

Combine like terms: 84 + -84 = 0
0 + 53c = 10 + -84
53c = 10 + -84

Combine like terms: 10 + -84 = -74
53c = -74

Divide each side by '53'.
c = -1.396226415

Simplifying
c = -1.396226415

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