28(2x-3)-70*1=25(4-3x)

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Solution for 28(2x-3)-70*1=25(4-3x) equation: 



28(2x-3)-70*1=25(4-3x)

We move all terms to the left:

28(2x-3)-70*1-(25(4-3x))=0

We add all the numbers together, and all the variables

28(2x-3)-(25(-3x+4))-70*1=0

We add all the numbers together, and all the variables

28(2x-3)-(25(-3x+4))-70=0

We multiply parentheses

56x-(25(-3x+4))-84-70=0



We calculate terms in parentheses: -(25(-3x+4)), so:

25(-3x+4)

We multiply parentheses

-75x+100

Back to the equation:

-(-75x+100)



We add all the numbers together, and all the variables

56x-(-75x+100)-154=0

We get rid of parentheses

56x+75x-100-154=0

We add all the numbers together, and all the variables

131x-254=0

We move all terms containing x to the left, all other terms to the right

131x=254

x=254/131

x=1+123/131

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