28(3c+4)=2(c+6)+c

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Solution for 28(3c+4)=2(c+6)+c equation:


Simplifying
28(3c + 4) = 2(c + 6) + c

Reorder the terms:
28(4 + 3c) = 2(c + 6) + c
(4 * 28 + 3c * 28) = 2(c + 6) + c
(112 + 84c) = 2(c + 6) + c

Reorder the terms:
112 + 84c = 2(6 + c) + c
112 + 84c = (6 * 2 + c * 2) + c
112 + 84c = (12 + 2c) + c

Combine like terms: 2c + c = 3c
112 + 84c = 12 + 3c

Solving
112 + 84c = 12 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
112 + 84c + -3c = 12 + 3c + -3c

Combine like terms: 84c + -3c = 81c
112 + 81c = 12 + 3c + -3c

Combine like terms: 3c + -3c = 0
112 + 81c = 12 + 0
112 + 81c = 12

Add '-112' to each side of the equation.
112 + -112 + 81c = 12 + -112

Combine like terms: 112 + -112 = 0
0 + 81c = 12 + -112
81c = 12 + -112

Combine like terms: 12 + -112 = -100
81c = -100

Divide each side by '81'.
c = -1.234567901

Simplifying
c = -1.234567901

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