28(b-1)+8=4(7b-5)

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Solution for 28(b-1)+8=4(7b-5) equation:


Simplifying
28(b + -1) + 8 = 4(7b + -5)

Reorder the terms:
28(-1 + b) + 8 = 4(7b + -5)
(-1 * 28 + b * 28) + 8 = 4(7b + -5)
(-28 + 28b) + 8 = 4(7b + -5)

Reorder the terms:
-28 + 8 + 28b = 4(7b + -5)

Combine like terms: -28 + 8 = -20
-20 + 28b = 4(7b + -5)

Reorder the terms:
-20 + 28b = 4(-5 + 7b)
-20 + 28b = (-5 * 4 + 7b * 4)
-20 + 28b = (-20 + 28b)

Add '20' to each side of the equation.
-20 + 20 + 28b = -20 + 20 + 28b

Combine like terms: -20 + 20 = 0
0 + 28b = -20 + 20 + 28b
28b = -20 + 20 + 28b

Combine like terms: -20 + 20 = 0
28b = 0 + 28b
28b = 28b

Add '-28b' to each side of the equation.
28b + -28b = 28b + -28b

Combine like terms: 28b + -28b = 0
0 = 28b + -28b

Combine like terms: 28b + -28b = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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