28(f-1)=5(7f-3)

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Solution for 28(f-1)=5(7f-3) equation: 



28(f-1)=5(7f-3)

We move all terms to the left:

28(f-1)-(5(7f-3))=0

We multiply parentheses

28f-(5(7f-3))-28=0



We calculate terms in parentheses: -(5(7f-3)), so:

5(7f-3)

We multiply parentheses

35f-15

Back to the equation:

-(35f-15)



We get rid of parentheses

28f-35f+15-28=0

We add all the numbers together, and all the variables

-7f-13=0

We move all terms containing f to the left, all other terms to the right

-7f=13

f=13/-7

f=-1+6/7

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