28(r+3)-42=7(4r+6)

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Solution for 28(r+3)-42=7(4r+6) equation: 



28(r+3)-42=7(4r+6)

We move all terms to the left:

28(r+3)-42-(7(4r+6))=0

We multiply parentheses

28r-(7(4r+6))+84-42=0



We calculate terms in parentheses: -(7(4r+6)), so:

7(4r+6)

We multiply parentheses

28r+42

Back to the equation:

-(28r+42)



We add all the numbers together, and all the variables

28r-(28r+42)+42=0

We get rid of parentheses

28r-28r-42+42=0

We add all the numbers together, and all the variables

=0

r=0/1

r=0

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