28(z-1)=38z

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Solution for 28(z-1)=38z equation: 



28(z-1)=38z

We move all terms to the left:

28(z-1)-(38z)=0

We add all the numbers together, and all the variables

-38z+28(z-1)=0

We multiply parentheses

-38z+28z-28=0

We add all the numbers together, and all the variables

-10z-28=0

We move all terms containing z to the left, all other terms to the right

-10z=28

z=28/-10

z=-2+4/5

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