28(z-5)=24z

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Solution for 28(z-5)=24z equation:


Simplifying
28(z + -5) = 24z

Reorder the terms:
28(-5 + z) = 24z
(-5 * 28 + z * 28) = 24z
(-140 + 28z) = 24z

Solving
-140 + 28z = 24z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-24z' to each side of the equation.
-140 + 28z + -24z = 24z + -24z

Combine like terms: 28z + -24z = 4z
-140 + 4z = 24z + -24z

Combine like terms: 24z + -24z = 0
-140 + 4z = 0

Add '140' to each side of the equation.
-140 + 140 + 4z = 0 + 140

Combine like terms: -140 + 140 = 0
0 + 4z = 0 + 140
4z = 0 + 140

Combine like terms: 0 + 140 = 140
4z = 140

Divide each side by '4'.
z = 35

Simplifying
z = 35

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