28+(x)(x)=(x-6)(x-2)

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Solution for 28+(x)(x)=(x-6)(x-2) equation: 



28+(x)(x)=(x-6)(x-2)

We move all terms to the left:

28+(x)(x)-((x-6)(x-2))=0

We multiply parentheses ..

-((+x^2-2x-6x+12))+xx+28=0



We calculate terms in parentheses: -((+x^2-2x-6x+12)), so:

(+x^2-2x-6x+12)

We get rid of parentheses

x^2-2x-6x+12

We add all the numbers together, and all the variables

x^2-8x+12

Back to the equation:

-(x^2-8x+12)



We get rid of parentheses

-x^2+8x+xx-12+28=0

We add all the numbers together, and all the variables

-1x^2+8x+xx+16=0

We move all terms containing x to the left, all other terms to the right

-1x^2+8x+xx=-16

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