28+2y-5=9y-12-2y

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Solution for 28+2y-5=9y-12-2y equation: 



28+2y-5=9y-12-2y

We move all terms to the left:

28+2y-5-(9y-12-2y)=0

We add all the numbers together, and all the variables

2y-(7y-12)+28-5=0

We add all the numbers together, and all the variables

2y-(7y-12)+23=0

We get rid of parentheses

2y-7y+12+23=0

We add all the numbers together, and all the variables

-5y+35=0

We move all terms containing y to the left, all other terms to the right

-5y=-35

y=-35/-5

y=+7

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