28+3(x-2)=12-(3x+8)

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Solution for 28+3(x-2)=12-(3x+8) equation: 



28+3(x-2)=12-(3x+8)

We move all terms to the left:

28+3(x-2)-(12-(3x+8))=0

We multiply parentheses

3x-(12-(3x+8))-6+28=0



We calculate terms in parentheses: -(12-(3x+8)), so:

12-(3x+8)

determiningTheFunctionDomain
-(3x+8)+12

We get rid of parentheses

-3x-8+12

We add all the numbers together, and all the variables

-3x+4

Back to the equation:

-(-3x+4)



We add all the numbers together, and all the variables

3x-(-3x+4)+22=0

We get rid of parentheses

3x+3x-4+22=0

We add all the numbers together, and all the variables

6x+18=0

We move all terms containing x to the left, all other terms to the right

6x=-18

x=-18/6

x=-3

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