28+4c=4(c+7)

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Solution for 28+4c=4(c+7) equation: 



28+4c=4(c+7)

We move all terms to the left:

28+4c-(4(c+7))=0



We calculate terms in parentheses: -(4(c+7)), so:

4(c+7)

We multiply parentheses

4c+28

Back to the equation:

-(4c+28)



We get rid of parentheses

4c-4c-28+28=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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