28+4t=4(t+7)

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Solution for 28+4t=4(t+7) equation: 



28+4t=4(t+7)

We move all terms to the left:

28+4t-(4(t+7))=0



We calculate terms in parentheses: -(4(t+7)), so:

4(t+7)

We multiply parentheses

4t+28

Back to the equation:

-(4t+28)



We get rid of parentheses

4t-4t-28+28=0

We add all the numbers together, and all the variables

=0

t=0/1

t=0

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