28+9y=2(3y+5)+2(2y+5)

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Solution for 28+9y=2(3y+5)+2(2y+5) equation: 



28+9y=2(3y+5)+2(2y+5)

We move all terms to the left:

28+9y-(2(3y+5)+2(2y+5))=0



We calculate terms in parentheses: -(2(3y+5)+2(2y+5)), so:

2(3y+5)+2(2y+5)

We multiply parentheses

6y+4y+10+10

We add all the numbers together, and all the variables

10y+20

Back to the equation:

-(10y+20)



We get rid of parentheses

9y-10y-20+28=0

We add all the numbers together, and all the variables

-1y+8=0

We move all terms containing y to the left, all other terms to the right

-y=-8

y=-8/-1

y=+8

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