28+r=2(4r+7)

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Solution for 28+r=2(4r+7) equation: 



28+r=2(4r+7)

We move all terms to the left:

28+r-(2(4r+7))=0



We calculate terms in parentheses: -(2(4r+7)), so:

2(4r+7)

We multiply parentheses

8r+14

Back to the equation:

-(8r+14)



We get rid of parentheses

r-8r-14+28=0

We add all the numbers together, and all the variables

-7r+14=0

We move all terms containing r to the left, all other terms to the right

-7r=-14

r=-14/-7

r=+2

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