28+x=(30+x)*(19/20)

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Solution for 28+x=(30+x)*(19/20) equation: 



28+x=(30+x)(19/20)

We move all terms to the left:

28+x-((30+x)(19/20))=0

We add all the numbers together, and all the variables

x-((x+30)(+19/20))+28=0

We multiply parentheses ..

-((+19x^2+30*19/20))+x+28=0

We multiply all the terms by the denominator


-((+19x^2+30*19+x*20))+28*20))=0



We calculate terms in parentheses: -((+19x^2+30*19+x*20)), so:

(+19x^2+30*19+x*20)

We get rid of parentheses

19x^2+x*20+30*19

We add all the numbers together, and all the variables

19x^2+x*20+570

Wy multiply elements

19x^2+20x+570

Back to the equation:

-(19x^2+20x+570)



We add all the numbers together, and all the variables

-(19x^2+20x+570)=0

We get rid of parentheses

-19x^2-20x-570=0

a = -19; b = -20; c = -570;
Δ = b2-4ac
Δ = -202-4·(-19)·(-570)
Δ = -42920
Delta is less than zero, so there is no solution for the equation

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