28-(0.3y)=0.7y-(12)

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Solution for 28-(0.3y)=0.7y-(12) equation: 



28-(0.3y)=0.7y-(12)

We move all terms to the left:

28-(0.3y)-(0.7y-(12))=0

We add all the numbers together, and all the variables

-(+0.3y)-(0.7y-12)+28=0

We get rid of parentheses

-0.3y-0.7y+12+28=0

We add all the numbers together, and all the variables

-1y+40=0

We move all terms containing y to the left, all other terms to the right

-y=-40

y=-40/-1

y=+40

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