28-(2c+3)=2(c+5)+5

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Solution for 28-(2c+3)=2(c+5)+5 equation:


Simplifying
28 + -1(2c + 3) = 2(c + 5) + 5

Reorder the terms:
28 + -1(3 + 2c) = 2(c + 5) + 5
28 + (3 * -1 + 2c * -1) = 2(c + 5) + 5
28 + (-3 + -2c) = 2(c + 5) + 5

Combine like terms: 28 + -3 = 25
25 + -2c = 2(c + 5) + 5

Reorder the terms:
25 + -2c = 2(5 + c) + 5
25 + -2c = (5 * 2 + c * 2) + 5
25 + -2c = (10 + 2c) + 5

Reorder the terms:
25 + -2c = 10 + 5 + 2c

Combine like terms: 10 + 5 = 15
25 + -2c = 15 + 2c

Solving
25 + -2c = 15 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
25 + -2c + -2c = 15 + 2c + -2c

Combine like terms: -2c + -2c = -4c
25 + -4c = 15 + 2c + -2c

Combine like terms: 2c + -2c = 0
25 + -4c = 15 + 0
25 + -4c = 15

Add '-25' to each side of the equation.
25 + -25 + -4c = 15 + -25

Combine like terms: 25 + -25 = 0
0 + -4c = 15 + -25
-4c = 15 + -25

Combine like terms: 15 + -25 = -10
-4c = -10

Divide each side by '-4'.
c = 2.5

Simplifying
c = 2.5

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