28-(2c+3)=2(c+6)+c

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Solution for 28-(2c+3)=2(c+6)+c equation: 



28-(2c+3)=2(c+6)+c

We move all terms to the left:

28-(2c+3)-(2(c+6)+c)=0

We get rid of parentheses

-2c-(2(c+6)+c)-3+28=0



We calculate terms in parentheses: -(2(c+6)+c), so:

2(c+6)+c

We add all the numbers together, and all the variables

c+2(c+6)

We multiply parentheses

c+2c+12

We add all the numbers together, and all the variables

3c+12

Back to the equation:

-(3c+12)



We add all the numbers together, and all the variables

-2c-(3c+12)+25=0

We get rid of parentheses

-2c-3c-12+25=0

We add all the numbers together, and all the variables

-5c+13=0

We move all terms containing c to the left, all other terms to the right

-5c=-13

c=-13/-5

c=2+3/5

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