28-(2c+3)=2c+10+c

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Solution for 28-(2c+3)=2c+10+c equation: 



28-(2c+3)=2c+10+c

We move all terms to the left:

28-(2c+3)-(2c+10+c)=0

We add all the numbers together, and all the variables

-(2c+3)-(3c+10)+28=0

We get rid of parentheses

-2c-3c-3-10+28=0

We add all the numbers together, and all the variables

-5c+15=0

We move all terms containing c to the left, all other terms to the right

-5c=-15

c=-15/-5

c=+3

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