28-(2c+4)=2(c=7)+c

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Solution for 28-(2c+4)=2(c=7)+c equation: 



28-(2c+4)=2(c=7)+c

We move all terms to the left:

28-(2c+4)-(2(c)=0

We get rid of parentheses

-2c-(2c+28-4=0

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