28-(2c-3)=2(c+5)+c

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Solution for 28-(2c-3)=2(c+5)+c equation:


Simplifying
28 + -1(2c + -3) = 2(c + 5) + c

Reorder the terms:
28 + -1(-3 + 2c) = 2(c + 5) + c
28 + (-3 * -1 + 2c * -1) = 2(c + 5) + c
28 + (3 + -2c) = 2(c + 5) + c

Combine like terms: 28 + 3 = 31
31 + -2c = 2(c + 5) + c

Reorder the terms:
31 + -2c = 2(5 + c) + c
31 + -2c = (5 * 2 + c * 2) + c
31 + -2c = (10 + 2c) + c

Combine like terms: 2c + c = 3c
31 + -2c = 10 + 3c

Solving
31 + -2c = 10 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
31 + -2c + -3c = 10 + 3c + -3c

Combine like terms: -2c + -3c = -5c
31 + -5c = 10 + 3c + -3c

Combine like terms: 3c + -3c = 0
31 + -5c = 10 + 0
31 + -5c = 10

Add '-31' to each side of the equation.
31 + -31 + -5c = 10 + -31

Combine like terms: 31 + -31 = 0
0 + -5c = 10 + -31
-5c = 10 + -31

Combine like terms: 10 + -31 = -21
-5c = -21

Divide each side by '-5'.
c = 4.2

Simplifying
c = 4.2

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