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28-(3c+4)=2(c+3)
We move all terms to the left:
28-(3c+4)-(2(c+3))=0
We get rid of parentheses
-3c-(2(c+3))-4+28=0
We calculate terms in parentheses: -(2(c+3)), so:We add all the numbers together, and all the variables
2(c+3)
We multiply parentheses
2c+6
Back to the equation:
-(2c+6)
-3c-(2c+6)+24=0
We get rid of parentheses
-3c-2c-6+24=0
We add all the numbers together, and all the variables
-5c+18=0
We move all terms containing c to the left, all other terms to the right
-5c=-18
c=-18/-5
c=3+3/5
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