28-(3c+4)=2(c+6)+3

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Solution for 28-(3c+4)=2(c+6)+3 equation: 



28-(3c+4)=2(c+6)+3

We move all terms to the left:

28-(3c+4)-(2(c+6)+3)=0

We get rid of parentheses

-3c-(2(c+6)+3)-4+28=0



We calculate terms in parentheses: -(2(c+6)+3), so:

2(c+6)+3

We multiply parentheses

2c+12+3

We add all the numbers together, and all the variables

2c+15

Back to the equation:

-(2c+15)



We add all the numbers together, and all the variables

-3c-(2c+15)+24=0

We get rid of parentheses

-3c-2c-15+24=0

We add all the numbers together, and all the variables

-5c+9=0

We move all terms containing c to the left, all other terms to the right

-5c=-9

c=-9/-5

c=1+4/5

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