28-(3c+4)=2(c+6)+c=2

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Solution for 28-(3c+4)=2(c+6)+c=2 equation: 



28-(3c+4)=2(c+6)+c=2

We move all terms to the left:

28-(3c+4)-(2(c+6)+c)=0

We get rid of parentheses

-3c-(2(c+6)+c)-4+28=0



We calculate terms in parentheses: -(2(c+6)+c), so:

2(c+6)+c

We add all the numbers together, and all the variables

c+2(c+6)

We multiply parentheses

c+2c+12

We add all the numbers together, and all the variables

3c+12

Back to the equation:

-(3c+12)



We add all the numbers together, and all the variables

-3c-(3c+12)+24=0

We get rid of parentheses

-3c-3c-12+24=0

We add all the numbers together, and all the variables

-6c+12=0

We move all terms containing c to the left, all other terms to the right

-6c=-12

c=-12/-6

c=+2

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