28-(3c+4)=2c(+3)+c

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Solution for 28-(3c+4)=2c(+3)+c equation: 



28-(3c+4)=2c(+3)+c

We move all terms to the left:

28-(3c+4)-(2c(+3)+c)=0

We add all the numbers together, and all the variables

-(3c+4)-(2c3+c)+28=0

We get rid of parentheses

-3c-2c3-c-4+28=0

We add all the numbers together, and all the variables

-2c^3-4c+24=0

We do not support ecpression: c^3

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