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28-(3c+4)=2c+12+c
We move all terms to the left:
28-(3c+4)-(2c+12+c)=0
We add all the numbers together, and all the variables
-(3c+4)-(3c+12)+28=0
We get rid of parentheses
-3c-3c-4-12+28=0
We add all the numbers together, and all the variables
-6c+12=0
We move all terms containing c to the left, all other terms to the right
-6c=-12
c=-12/-6
c=+2
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