28-(3c-4)=2(c+6)+c

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Solution for 28-(3c-4)=2(c+6)+c equation: 


Simplifying
28 + -1(3c + -4) = 2(c + 6) + c

Reorder the terms:
28 + -1(-4 + 3c) = 2(c + 6) + c
28 + (-4 * -1 + 3c * -1) = 2(c + 6) + c
28 + (4 + -3c) = 2(c + 6) + c

Combine like terms: 28 + 4 = 32
32 + -3c = 2(c + 6) + c

Reorder the terms:
32 + -3c = 2(6 + c) + c
32 + -3c = (6 * 2 + c * 2) + c
32 + -3c = (12 + 2c) + c

Combine like terms: 2c + c = 3c
32 + -3c = 12 + 3c

Solving
32 + -3c = 12 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
32 + -3c + -3c = 12 + 3c + -3c

Combine like terms: -3c + -3c = -6c
32 + -6c = 12 + 3c + -3c

Combine like terms: 3c + -3c = 0
32 + -6c = 12 + 0
32 + -6c = 12

Add '-32' to each side of the equation.
32 + -32 + -6c = 12 + -32

Combine like terms: 32 + -32 = 0
0 + -6c = 12 + -32
-6c = 12 + -32

Combine like terms: 12 + -32 = -20
-6c = -20

Divide each side by '-6'.
c = 3.333333333

Simplifying
c = 3.333333333

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