28-(3x+4)=3x+12

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Solution for 28-(3x+4)=3x+12 equation: 



28-(3x+4)=3x+12

We move all terms to the left:

28-(3x+4)-(3x+12)=0

We get rid of parentheses

-3x-3x-4-12+28=0

We add all the numbers together, and all the variables

-6x+12=0

We move all terms containing x to the left, all other terms to the right

-6x=-12

x=-12/-6

x=+2

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