28-3(2w-1)=5w-3(5+w)

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Solution for 28-3(2w-1)=5w-3(5+w) equation: 



28-3(2w-1)=5w-3(5+w)

We move all terms to the left:

28-3(2w-1)-(5w-3(5+w))=0

We add all the numbers together, and all the variables

-3(2w-1)-(5w-3(w+5))+28=0

We multiply parentheses

-6w-(5w-3(w+5))+3+28=0



We calculate terms in parentheses: -(5w-3(w+5)), so:

5w-3(w+5)

We multiply parentheses

5w-3w-15

We add all the numbers together, and all the variables

2w-15

Back to the equation:

-(2w-15)



We add all the numbers together, and all the variables

-6w-(2w-15)+31=0

We get rid of parentheses

-6w-2w+15+31=0

We add all the numbers together, and all the variables

-8w+46=0

We move all terms containing w to the left, all other terms to the right

-8w=-46

w=-46/-8

w=5+3/4

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