28-3k=1-5(3+2k)

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Solution for 28-3k=1-5(3+2k) equation: 



28-3k=1-5(3+2k)

We move all terms to the left:

28-3k-(1-5(3+2k))=0

We add all the numbers together, and all the variables

-3k-(1-5(2k+3))+28=0



We calculate terms in parentheses: -(1-5(2k+3)), so:

1-5(2k+3)

determiningTheFunctionDomain
-5(2k+3)+1

We multiply parentheses

-10k-15+1

We add all the numbers together, and all the variables

-10k-14

Back to the equation:

-(-10k-14)



We get rid of parentheses

-3k+10k+14+28=0

We add all the numbers together, and all the variables

7k+42=0

We move all terms containing k to the left, all other terms to the right

7k=-42

k=-42/7

k=-6

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