28-5=2+3(3x+3)

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Solution for 28-5=2+3(3x+3) equation: 



28-5=2+3(3x+3)

We move all terms to the left:

28-5-(2+3(3x+3))=0

We add all the numbers together, and all the variables

-(2+3(3x+3))+23=0



We calculate terms in parentheses: -(2+3(3x+3)), so:

2+3(3x+3)

determiningTheFunctionDomain
3(3x+3)+2

We multiply parentheses

9x+9+2

We add all the numbers together, and all the variables

9x+11

Back to the equation:

-(9x+11)



We get rid of parentheses

-9x-11+23=0

We add all the numbers together, and all the variables

-9x+12=0

We move all terms containing x to the left, all other terms to the right

-9x=-12

x=-12/-9

x=1+1/3

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