28-5=3+2(x+3)

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Solution for 28-5=3+2(x+3) equation: 



28-5=3+2(x+3)

We move all terms to the left:

28-5-(3+2(x+3))=0

We add all the numbers together, and all the variables

-(3+2(x+3))+23=0



We calculate terms in parentheses: -(3+2(x+3)), so:

3+2(x+3)

determiningTheFunctionDomain
2(x+3)+3

We multiply parentheses

2x+6+3

We add all the numbers together, and all the variables

2x+9

Back to the equation:

-(2x+9)



We get rid of parentheses

-2x-9+23=0

We add all the numbers together, and all the variables

-2x+14=0

We move all terms containing x to the left, all other terms to the right

-2x=-14

x=-14/-2

x=+7

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