28-8z=4(z-5)

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Solution for 28-8z=4(z-5) equation: 



28-8z=4(z-5)

We move all terms to the left:

28-8z-(4(z-5))=0



We calculate terms in parentheses: -(4(z-5)), so:

4(z-5)

We multiply parentheses

4z-20

Back to the equation:

-(4z-20)



We get rid of parentheses

-8z-4z+20+28=0

We add all the numbers together, and all the variables

-12z+48=0

We move all terms containing z to the left, all other terms to the right

-12z=-48

z=-48/-12

z=+4

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