28-h=4(h-2)-24

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Solution for 28-h=4(h-2)-24 equation:



28-h=4(h-2)-24
We move all terms to the left:
28-h-(4(h-2)-24)=0
We add all the numbers together, and all the variables
-1h-(4(h-2)-24)+28=0
We calculate terms in parentheses: -(4(h-2)-24), so:
4(h-2)-24
We multiply parentheses
4h-8-24
We add all the numbers together, and all the variables
4h-32
Back to the equation:
-(4h-32)
We get rid of parentheses
-1h-4h+32+28=0
We add all the numbers together, and all the variables
-5h+60=0
We move all terms containing h to the left, all other terms to the right
-5h=-60
h=-60/-5
h=+12

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