28-x=2+(x+3)

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Solution for 28-x=2+(x+3) equation: 



28-x=2+(x+3)

We move all terms to the left:

28-x-(2+(x+3))=0

We add all the numbers together, and all the variables

-1x-(2+(x+3))+28=0



We calculate terms in parentheses: -(2+(x+3)), so:

2+(x+3)

determiningTheFunctionDomain
(x+3)+2

We get rid of parentheses

x+3+2

We add all the numbers together, and all the variables

x+5

Back to the equation:

-(x+5)



We get rid of parentheses

-1x-x-5+28=0

We add all the numbers together, and all the variables

-2x+23=0

We move all terms containing x to the left, all other terms to the right

-2x=-23

x=-23/-2

x=11+1/2

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